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Tutors Answer Your Questions about Linear-systems (FREE)
Question 47612: Please help!
If u=x-2 is an equation representing a line on a graph, which direction is the line moving, and what is the slope?
a. up and to the left, m=2
b. up and to the right, m=1
c. upand to the left, m=1
Thank you!
Click here to see answer by checkley71(8405)   |
Question 47914: I'm having a hard time with this problem. I'm not sure if I'm doing this right.
It says solve the system by the elimination method
7x+5y=42
4x-3y=24
doing this I came up with this 28x+20y=168
28x-21y=168
some how I end up with -1. I'm trying to cancell out the x but the 168 is bothering me, it doesnt look right. Please help me
Click here to see answer by 1980.vikas(7) |
Question 48598: Choose two different positive numbers. Then construct a system of two linear equations with two variables, such that its solution consists of exactly the two chosen numbers. Explain your method of creating the system.
Click here to see answer by stanbon(26256) |
Question 49622: A jeweler paid 1455 for a watch. He wants to price the watch for sale so that he can give the customer a 25% discount on the selling price and still make a profit of 30% on his cost. What selling price should he mark for the watch?
Click here to see answer by checkley71(8405) |
Question 49645: Solve for the variable:
2(y – 1)^2 = 4(y + 1)^2
2(y^2 – 2y + 1) = 4(y^2 + 2y + 1)
2y^2 – 4y + 2 = 4y^2 + 8y + 4
2y^2 – 4y^2 – 4y – 8y + 2 – 4
-2y^2 – 12y – 2 = 0
a = -2
b = -12
c = -2
2 +/- sqrt[-12^2 - (4)(-2)(-2)] / [(2)(-2)]
12 +/- sqrt[144 - 16] / -4
-3 +/- sqrt 128
Make sense? I have it in a Word Doc using Math Type.
Click here to see answer by gsmani_iyer(161) |
Question 50102: Hi, this question has me confused. It is suppose that the vertex of the parabola is y=3x^2-6x+k is (1,2). Find k.
Do I replace y with 2 and the x with 1 and come to a conclusion from there??? I'm not sure. Thanks.
Click here to see answer by stanbon(26256) |
Question 50099: Well I will start off saying I know I have the wrong answer somewhere and I know that because I put my answers into the original equations and they don't work. I have trouble when you throw that third variable in so if someone can tell what is right (if anything) and where I went wrong. Thanks!! Andrea
(a)
2x – y + z = 8
x + 2y + z = -3
x - 2y – z = 7
(1 & 3)
3x – 3y = 15
x – y = 5
2x = 4
x = 2
2 – y = 5
y = -3
2 + 2(-3) + z = -3
z = 1
(b)
3x - y - 2z = 11
x – 2y + 3z = 12
x + y - 2z = 5
(1 & 3) = (4)
4x – 4z = 16
(2 & 3) = (5)
x – 2y + 3z = 12
2x + 2y – 4z = 10
3x + z = 22
(4 & 5)
4x – 4z = 16
3x + z = 22
4x – 4z = 16
-12x + 4z = -88
-8x = -72
x = 9
3(9) + z = 22
27 + z = 22
z = -5
9 – y – 2(-5) = 5
9 – y + 10 = 5
19 – y = 5
-y = -14
y = 14
Click here to see answer by Earlsdon(4898) |
Question 50039: PLEASE HELP ME!!!
I need to find out the intercepts for x and y. i need the cordinants for them. for example, the integers of x is (#,0) and the integers of y is (0,#). well my problem to find out is what is the integers of 4x-y=3? please help me all you can, i really need to pass this class and i just dont get it.
Click here to see answer by tutorcecilia(2042) |
Question 50378: can you show me the detailed steps for solving for x in the following equation?
2.15x + 2.55*(1-x)=2.516
I can get as far as:
x=2.516-2.55*(1-x)/2.15
but I am unsure how to complete from there.
Thank you in advance for your help.
Scott
Click here to see answer by stanbon(26256) |
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