SOLUTION: It says to solve each system by substitution and elimination but I don't understand on how to do it. Y=-3x+4 Y=3x-2

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Question 999539: It says to solve each system by substitution and elimination but I don't understand on how to do it.
Y=-3x+4
Y=3x-2
Found 2 solutions by mananth, MathTherapy:
Answer by mananth(16946)   (Show Source): You can put this solution on YOUR website!
3 x + 1 y = 4 .............1
Total value
-3 x + 1 y = -2 .............2
Eliminate y
multiply (1)by -1
Multiply (2) by 1
-3 x -1 y = -4
-3 x + 1 y = -2
Add the two equations
-6 x = -6
/ -6
x = 1
plug value of x in (1)
3 x + 1 y = 4
3 + y = 4
y = 4 -3
y = 1
y = 1
x= 1
y= 1
SUBSTITUTION METHOD

3 x + 1 y = 4 .............1
1 y = 4 + -3 x
/ 1 =
y = 4 + -3 x
-3 x + 1 y = -2 .....................2
Substitute y in (2)
-3 x + 1 ( 4 + -3 x ) = -2
-3 x + 4 + -3 x = -2
-3 x -3 x = -6
-6 x = -6
/ -6
x= 1
Plug the value of x in (1)
3 x + 1 y = 4
3 * 1 + 1 y = 4
3 + 1 y = 4
1 y = 1
/ 1
y= 1
m.ananth@hotmail.ca



Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!
It says to solve each system by substitution and elimination but I don't understand on how to do it.
Y=-3x+4
Y=3x-2
ELIMINATION

y = - 3x + 4 --- eq (i)

y = 3x - 2 ----- eq (ii)

2y = 2 --------- Adding eqs (ii) & (i)

y = , or 

1 = - 3x + 4  ------- Substituting 1 for y in eq (i)

3x = 4 - 1

3x = 3

x = , or 

SUBSTITUTION

Since both equations have already been solved for y, then just set them equal to each other, as follows: - 3x + 4 = 3x - 2

Solve this for x, then find y 

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