SOLUTION: Two boats traveling in the same direction leave a harbor at noon. After 3 hours they are 60 miles apart. If one boat travels twice as fast as the other,find the avarage rate of eac
Algebra.Com
Question 99299: Two boats traveling in the same direction leave a harbor at noon. After 3 hours they are 60 miles apart. If one boat travels twice as fast as the other,find the avarage rate of each boat.
Answer by edjones(8007) (Show Source): You can put this solution on YOUR website!
let a be the faster boat
a=2b
a=b+20
b+20=2b
b=20 mph
a=40 mph
Ed
RELATED QUESTIONS
Two boats traveling in the same direction leave a harbor at noon. After 3 hr they are 60... (answered by khalsa)
Two boats leave the dock at the same time going in the same direction.
The first boat... (answered by mananth)
Two boats leave the dock at the same time and travel in opposite directions. One travels... (answered by MathLover1)
Two boats leave a ramp traveling in opposite directions. The second boat is 10 miles per... (answered by rfer)
Two boats leave a ramp traveling in opposite directions.The second boat is
10 miles per... (answered by checkley75)
two fishing boats depart a harbor at the same time, one traveling east, the other south.... (answered by mananth)
Two motorboats leave the dock at the same time and travel in opposite directions. One... (answered by josgarithmetic,advanced_Learner,ikleyn)
Two boats leave a ramp traveling in opposite directions. The second boat is 10 miles per... (answered by checkley71)
Two fishing boats depart a harbor at the same time, traveling east, the other south. The... (answered by ankor@dixie-net.com)