SOLUTION: 8x+5y=11 and 3x-4y=10
Algebra.Com
Question 984768: 8x+5y=11 and 3x-4y=10
Answer by Cromlix(4381) (Show Source): You can put this solution on YOUR website!
Hi there,
8x + 5y = 11.....(1)
3x - 4y = 10.....(2)
Multiply (1) by 4 and
(2) by 5
32x + 20y = 44....(1)
15x - 20y = 50....(20
Add (1) + (2)
47x = 94
x = 2
Substitute x = 2 into
Equation (1)
8x + 5y = 11
8(2) + 5y = 11
16 + 5y = 11
5y = 11 - 16
5y = -5
y = -1
x = 2: y = -1
Hope this helps:-)
RELATED QUESTIONS
8x+5y-3x-4y (answered by alicealc)
x=5y... (answered by edjones)
x=5y
3x-4y=11
(answered by Tatiana_Stebko)
1. Solve the system by substitution.
A) 3x+4y=11. B) 3x+2y=6
-8x-y=19. (answered by josgarithmetic,MathTherapy)
(-8x+5y-12)-6(2x-4y-10) (answered by jim_thompson5910)
How would I solve these systems?
1)x+5y=4
3x-7y=-10
2)-5x+3y=6
x-y=4
(answered by elima)
Solve by elimination:
1.8x + 11y= 20
5x - 11y= -59
2. 2x + 18y= -9
4x + 18y= -27
(answered by jim_thompson5910)
Solve and Graph:
4x=5y=-2 4y-x=11
and...
3x+y=2... (answered by checkley71)
Graph the following system:
3x-5y=-9
5x-6y=-8
and
4x+5y=-2
4y-x+11
(answered by jim_thompson5910)