SOLUTION: x + y = 0 x - y + 2 = 0 This is really confusing me! I get that x=0 and y=0. Is this right? If not then what is correct? How would I graph it? Very urgent. Can you h

Algebra ->  Coordinate Systems and Linear Equations -> SOLUTION: x + y = 0 x - y + 2 = 0 This is really confusing me! I get that x=0 and y=0. Is this right? If not then what is correct? How would I graph it? Very urgent. Can you h      Log On


   



Question 984332: x + y = 0
x - y + 2 = 0
This is really confusing me! I get that x=0 and y=0. Is this right? If not then what is correct? How would I graph it? Very urgent. Can you help me right now? My email is lifeisgood4a@cotc.net
Thank you!

Found 3 solutions by macston, Fombitz, solver91311:
Answer by macston(5194) About Me  (Show Source):
You can put this solution on YOUR website!
.
x+y=0 (red line on graph)
x=-y
.
x-y+2=0 Substitute for x. (green line on graph)
-y-y+2=0
-2y=-2
y=1
.
x=-y
x=-1
.
ANSWER:(-1,1)
+graph%28+500%2C+500%2C+-5%2C+5%2C+-5%2C+5%2C+-x%2Cx%2B2%29+

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
No it's not right.
Check using the original equations.
x%2By=0
0%2B0=0
0=0
True, so far, so good.
x-y%2B2=0
0-0%2B2=0
2=0
False, so this can't be the solution.
.
.
.
Add the two equations together to eliminate y.
x%2By%2Bx-y%2B2=0
2x%2B2=0
2x=-2
x=-1
Then use either equation to solve for y.
x%2By=0
-1%2By=0
y=1
(-1,1)
.
.
.
Graph the two equations.
x%2By=0
y=-x
.
.
graph%28300%2C300%2C-5%2C5%2C-5%2C5%2C-x%29
.
.
x-y%2B2=0
y=x%2B2
.
.
graph%28300%2C300%2C-5%2C5%2C-5%2C5%2C-x%2Cx%2B2%29

Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


What makes you think that and ? could be 100 Billion if is negative 100 Billion from the first equation alone, and the second equation tells you that they can't both be zero because that would mean that which would mean that which would cause a catastrophic rip in the space-time continuum. I don't think you want to be responsible for the utter destruction of the universe, do you?

Put both equations into standard form, that is:




Now, just since you have two of the same variable with opposite signs, you can add the two equations and eliminate the variable altogether. , , and , hence:



which is to say:



You should be able to handle discovering the value of from here. Once you know you can substitute that value into either of your original equations and then solve for .

Be careful. The fate of the universe is in your hands.

John

My calculator said it, I believe it, that settles it