SOLUTION: find two consecutive even integers such that the smaller added to three times the larger gives a sum of 46

Question 97819This question is from textbook
: find two consecutive even integers such that the smaller added to three times the larger gives a sum of 46 This question is from textbook

Found 2 solutions by checkley71, edjones:
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
LET (E) BE THE SMALLEST EVEN NUMBER
LET (E+2) BE THE LARGER EVEN NUMBER.
E+3(E+2)=46
E+3E+6=46
4E=46-6
4E=40
E=40/4
E=10 ANSWER FOR THE SMALLER EVEN NUMBER
10+2=12 ANSWER FOR THE LARGER EVEN NUMBER.
PROOF
10+3*12=46
10+36=46
46=46

Answer by edjones(8007) (Show Source): You can put this solution on YOUR website!
let the 2 integers be: x, x+1
x+3(x+1)=46
x+3x+3=46
4x+3=46
4x=43
x=10.75
there is no answer x is not an integer.
Check:
10.75+3(10.75+1)=46
10.75+32.25+3=46
Ed
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