SOLUTION: find two consecutive odd intergers such that twice the larger is 17 more than the smaller.

SOLUTION: find two consecutive odd intergers such that twice the larger is 17 more than the smaller.

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Question 97815This question is from textbook
: find two consecutive odd intergers such that twice the larger is 17 more than the smaller. This question is from textbook

Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
X=THE SMALLER ODD INTERGER & (X+2) IS THE LARGER ODD INTERGER.
2(X+2)=X+17
2X+4=X+17
2X-X=17-4
X=13 ANSWER FOR THE SMALLER ODD INTERGER.
13+2=15 ANSWER FOR THE LARGER ODD INTERGER.
PROOF
2*15=13+17
30=30

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