# SOLUTION: how do i find sloope of an equation that looks like this X-2/3y=1/4 and . . . 2X-5Y=0

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 Click here to see ALL problems on Linear-systems Question 96367: how do i find sloope of an equation that looks like this X-2/3y=1/4 and . . . 2X-5Y=0Found 2 solutions by elima, checkley71:Answer by elima(1433)   (Show Source): You can put this solution on YOUR website!You need to put them in slope intercept form; y=mx+b, where m = slope; X-2/3y=1/4 subtract x from both sides: -y=-x+ multiply the reciprocal of to both sides; y=-x+ y=X- slope = 2X-5Y=0 -5y=-2x+0 y=x slope = Answer by checkley71(8403)   (Show Source): You can put this solution on YOUR website!Y=mX+b IS THE LINE EQUATION WHERE m=SLOPE. NOW PUT YOUR EQUATION IN THIS FORM: X-2/3Y=1/4 -2/3Y=-X+1/4 Y=-X/(-2/3)+(1/4)/(-2/3) TO DIVIDE BY A FRACTION IN THE DENOMINATOR INVERT THE FRACTION IN THE DENOMINATOR & MULTIPLY BY THE NUMERATOR THUS: Y=-X(-3/2)+(1/4)(-3/2) Y=3X/2-3/8 THIS LINE HAS A SLOPE(m)=3/2 ------------------------------------------------------- 2X-5Y=0 -5Y=-2X Y=-2X/-5 Y=2X/5 THIS LINE HAS A SLOPE(m)=2/5