SOLUTION: solve this linear system using the method of substitution:
1/4x + 1/2y = -5/12
2x - y= -4/3
I try my best work , hope anyone can check and correct if I did it wrong. Thank
Algebra.Com
Question 963137: solve this linear system using the method of substitution:
1/4x + 1/2y = -5/12
2x - y= -4/3
I try my best work , hope anyone can check and correct if I did it wrong. Thank you =)
step 1:
2x - y =-4/3
-y= -2x - 4/3
y= 2x + 4/3
Step 2:
1/4x + 1/2 (2x +4/3) = -5/12
1/4x + x +2/3= -5/12
5/4x = -5/12 - 2/3
5/4x = -13/12
x = -13/15
step 3:
2( -13/15) - y= -4/3
-26/15 - y = -4/3
-y = -4/3 +26/15
-y = -2/5
y= 2/5
Found 2 solutions by josgarithmetic, macston:
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
Sign mistake:
Answer by macston(5194) (Show Source): You can put this solution on YOUR website!
If you plug your answers back into the equations, you'll find they don't check.
The error is in Step 3
Step 3:
2( -13/15) - y= -4/3
-26/15 - y = -4/3
-y = -4/3 +26/15 (-20/15+26/15=6/15=2/5)
-y = -2/5 ( This should be +2/5)
y= 2/5 (This should be -2/5)
CHECK:
2x - y= -4/3
2(-13/15)-(-2/5)=-4/3
-26/15+6/15=-4/3
-20/15=-4/3
-4/3=-4/3
-------------
1/4x + 1/2y = -5/12
1/4(-13/15)+1/2(-2/5)=-5/12
-13/60-1/5=-5/12
-13/60-12/60=-5/12
-25/60=-5/12
-5/12=-5/12
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