SOLUTION: The width of a rectangular TV screen is 5.7 in. more than the height. If the diagonal is 27.0 in., find the dimensions of the screen.

Question 956293: The width of a rectangular TV screen is 5.7 in. more than the height. If the diagonal is 27.0 in., find the dimensions of the screen.
Answer by amarjeeth123(569) (Show Source): You can put this solution on YOUR website!
Let the height be x.
Then the width is (x+5.7).
The diagonal is 27.0 in.
x^2+(x+5.7)^2=27^2
x^2+x^2+11.4x+32.49=729
2x^2+11.4x-696.51=0

Solved by pluggable solver: SOLVE quadratic equation with variable

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=5702.04 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: 16.0279633435389, -21.7279633435389. Here's your graph:

Height=16.027
Width=21.727
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