SOLUTION: Use the elimination method to solve the following system of equations. what is x-4y+3z=1
-x+y-5z=-10
2x-4y+3z=-3
Thank you!
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Question 930486: Use the elimination method to solve the following system of equations. what is x-4y+3z=1
-x+y-5z=-10
2x-4y+3z=-3
Thank you!
Answer by TimothyLamb(4379) (Show Source): You can put this solution on YOUR website!
x-4y+3z=1
-x+y-5z=-10
2x-4y+3z=-3
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put the system of linear equations into standard form
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x-4y+3z=1
-x+y-5z=-10
2x-4y+3z=-3
---
copy and paste the above standard form linear equations in to this solver:
https://sooeet.com/math/system-of-linear-equations-solver.php
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solution:
x = -4
y = 1
z = 3
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now by elimination:
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x - 4y + 3z = 1
-x + y - 5z = -10
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add the above two equations:
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-3y - 2z = -9
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2(-x + y - 5z = -10)
2x - 4y + 3z = -3
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-2x + 2y - 10z = -20
2x - 4y + 3z = -3
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add the above two equations:
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-2y - 7z = -23
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-3(-2y - 7z = -23)
2(-3y - 2z = -9)
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6y + 21z = 69
-6y - 4z = -18
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add the above two equations:
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17z = 51
z = 3
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-3y - 2z = -9
-3y - 2*3 = -9
-3y = -3
y = 1
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x - 4y + 3z = 1
x = 1 - (- 4y + 3z)
x = 1 + 4y - 3z
x = 1 + 4*1 - 3*3
x = -4
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solution by elimination:
x = -4
y = 1
z = 3
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