How do I solve this system using elimination? In steps please.
6/x-3/y=-4 and 9/x+9/y=21
Let , and
Then:
becomes: 6a 3b = - 4 ------- eq (i)
becomes: 9a + 9b = 21_____3(3a + 3b) = 3(7)_____3a + 3b = 7 ---------- eq (ii)
9a = 3 --------- Adding eqs (ii) &(i)
, or
--------- Substituting 1/3 for a in eq (i)
2 3b = 4
3b = 4 2
3b = 6
, or
Since , then , or
Now, since , then
Since b = 2, then
Now, since , then
You can do the check!!
===================
Send comments, thank-yous, and inquiries to D at MathMadEzy@aol.com.
Further help is available, online or in-person, for a fee, obviously.
For FREE info and answers to questions about the ASVAB exam, the NYS 3 8 city/state wide exams,GENERAL
MATH and HOMEWORK QUESTIONS, or MATH QUESTIONS related to the Regents Integrated Algebra,
Regents Geometry, Regents Algebra 2/Trigonometry, SHSAT, COOP/HSPT/TACHS, PSAT, SAT, ACT, SSAT/ISEE,
GRE, CLEP, and the TASC/GED, you can visit: http://asvabstudyzone.freeforums.net/.