SOLUTION: How do I solve this system using elimination? In steps please. 6/x-3/y=-4 and 9/x+9/y=21

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Question 930458: How do I solve this system using elimination? In steps please.
6/x-3/y=-4 and 9/x+9/y=21

Found 3 solutions by Alan3354, TimothyLamb, MathTherapy:
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
How do I solve this system using elimination? In steps please.
6/x-3/y=-4 and 9/x+9/y=21
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Sub for 1/x and 1/y, r & s will work
6r - 3s = -4
3r + 3s = 7 (divided by 3)
------------------------------- Add
Then sub back.

Answer by TimothyLamb(4379)   (Show Source): You can put this solution on YOUR website!
6/x - 3/y = -4
9/x + 9/y = 21
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6y/xy - 3x/xy = -4
6y - 3x = -4xy
---
9/x + 9/y = 21
9y/xy + 9x/xy = 21
9y + 9x = 21xy
---
6y - 3x = -4xy
9y + 9x = 21xy
---
21(6y - 3x = -4xy)
4(9y + 9x = 21xy)
---
21*6y - 21*3x = -21*4xy
4*9y + 4*9x = 4*21xy
---
add the two equations:
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21*6y + 4*9y - 21*3x + 4*9x = 0
(21*6 + 4*9)y - (21*3 + 4*9)x = 0
162y - 99x = 0
162y = 99x
---
answer:
y = (99/162)x
---
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Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!

How do I solve this system using elimination? In steps please.
6/x-3/y=-4 and 9/x+9/y=21
Let , and 
Then:
becomes: 6a – 3b = - 4 ------- eq (i)
becomes: 9a + 9b = 21_____3(3a + 3b) = 3(7)_____3a + 3b = 7 ---------- eq (ii)
9a = 3 --------- Adding eqs (ii) &(i)
, or
--------- Substituting 1/3 for a in eq (i)
2 – 3b = – 4
– 3b = – 4 – 2
– 3b = – 6
, or
Since , then , or
Now, since , then
Since b = 2, then
Now, since , then
You can do the check!!
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