SOLUTION: ]the singles court in tennis is 4 yards longer than it is wide. if its perimeter is 44 yards, then what are the length and width?]
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Question 924835: ]the singles court in tennis is 4 yards longer than it is wide. if its perimeter is 44 yards, then what are the length and width?]
Found 2 solutions by TimothyLamb, tutoringisfun:
Answer by TimothyLamb(4379) (Show Source): You can put this solution on YOUR website!
L = w + 4
2L + 2w = 44
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2L + 2w = 44
2(w + 4) + 2w = 44
2w + 8 + 2w = 44
4w = 36
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w = 9 yards
L = 13 yards
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Answer by tutoringisfun(17) (Show Source): You can put this solution on YOUR website!
Good afternoon student. I hope this is helpful to you. Thank you for choosing Algebra.com.
1. Write down pertinent information from the problem.
P=44
L=w+4
2. Although it is not given in the problem, one needs to use the following formula for determining the perimeter of a rectangle
P=2L+2W
3. Plug in the values given in the problem and solve:
44=2(w+4)+2W
distribute the 2 to get rid of the parentheses:
44=2W+8+2W
combine like terms:
44=4W+8
subtract 8 from each side because we need to get w by itself
44-8=4W+8-8
on the right, the 8's cancel out leaving:
36=4W
Divide both sides by 4
36/4=4W/4
Solve
9=W
4. Solve the following equation for L
L=W+4
substitute 9 for W and add
L=9+4
13=L
5. to check your answer plug the numbers for L,W into the formula for perimeter from above
P=2L+2W
44=2(13)+2(9)
44=26+18
44=44
I hope this was helpful to you. If you desire PAID assistance, you can contact me via the following websites
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or via my facebook page as mentioned in my profile. Good Luck in school.
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