SOLUTION: graph a parabola in Vertex y=−4x 2 +40x−95.

Algebra.Com
Question 915033: graph a parabola in Vertex
y=−4x 2 +40x−95.

Answer by josgarithmetic(39620)   (Show Source): You can put this solution on YOUR website!
You may have other examples like that one to do. This lesson will help you understand all of them:

http://www.algebra.com/my/Completing-the-Square-to-Solve-General-Quadratic-Equation.lesson?content_action=show_dev

You will be able to put into standard form and can then read the vertex point from the standard form equation. Also, solving for the roots (zeros) is easily done from standard form.

RELATED QUESTIONS

Write the quadratic function in the form g(x)=a(x−h)^2+k Then, give the... (answered by josgarithmetic)
For each of the following expressions, simplify by expanding any brackets and collecting... (answered by user_dude2008)
Find the vertex, focus, and directrix of the parabola given by the equation. Sketch the... (answered by ewatrrr)
1. Let f(x) = 2x^2 − 8x − 7. What is the quadratic in vertex form that is y (answered by josgarithmetic)
Let f(x) = 2x^2 − 8x − 7. Write the quadratic in vertex form (that is y... (answered by josgarithmetic)
1. Let f(x) = 2x^2 − 8x − 7. Write the quadratic in vertex form (that is y... (answered by stanbon)
Let f(x) = 2x^2 − 8x − 7. What is the quadratic in vertex form that is y = (answered by stanbon)
Graph. y = −x − 1 (answered by macston)
The graph of the equation x^2 + y^2 + 8x − 10y − 40 = 0 is which of the... (answered by Fombitz,htmentor)