h = hundreds digit
t = tens digit
u = ones or units digit
100h+10t+u = the number
100u+10t+h = the number reversed
The sum of the digits of a three digit number is 13.
h + t + u = 13
When 11 is subtracted from the sum of the hundreds digit and tens digit, the answer is equal to the units digit.
(h+t) - 11 = u
h + t - 11 = u
h + t - u = 11
Additionally, when the digits are reversed, the new value is 495 less than the original number.
100u+10t+h = (100h+10t+u) - 495
100u + 10t + h = 100h + 10t + u - 495
99u - 99h = -495 <-- divide thru by 99
u - h = -5 <-- get in h,t,u order
-h + u = -5
Can you solve that system? If not post again asking how.
The number is 661
Edwin