SOLUTION: a man and his dog running on a straight beach.at a given point in time the dog is 12m from his owner who starting in a direction perpendicular to the beach with a certain constant

Question 900265: a man and his dog running on a straight beach.at a given point in time the dog is 12m from his owner who starting in a direction perpendicular to the beach with a certain constant speed. the dog runs twice as fast and always to wards his owner where do the man and his dog meet?
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
a man and his dog running on a straight beach.at a given point in time the dog is 12m from his owner who starting in a direction perpendicular to the beach with a certain constant speed.
the dog runs twice as fast and always to wards his owner where do the man and his dog meet?
:
speed and distance vary directly
let d = distance the man travels from the beach,when the dog reaches him
then
2d = distance run by the dog
:
Actually the dog would probably run a curved path looking at the owner as he ran.
We will assume the dog ran to a point where the man is, a pythag problem
a^2 + b^2 = c^2, where
a = d
b = 12
c = 2d
d^2 + 12^2 = (2d)^2
d^2 + 144 = 4d^2
144 = 4d^2 - d^2
144 = 3d^2
d^2 = 144/3
d^2 = 48
d =
d = or about 6.93 meters

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