SOLUTION: When solving the system of equations by graphing first each equation how do we solve this problem? Equations: 3x+3y=12 y=-x-4 when trying to find out what type of solution do

Question 890643: When solving the system of equations by graphing first each equation how do we solve this problem?
Equations:
3x+3y=12
y=-x-4
when trying to find out what type of solution do we make a output input table for both equations? please solve equation and graph and show me how you did it!
Answer by fcabanski(1391) (Show Source): You can put this solution on YOUR website!
Both of these equations are for straight lines. Any equation of the form ax + by = c (standard form) or y=mx+b (slope intercept form) is an equation of a straight line. To graph a line, find two points. Connect them.

The graph will show the solution for this equation as the point(s) where the lines intersect.

The easiest points to find are the intercepts. What is x when y = 0? And what is y when x = 0

For equation 1: 3x +3(0) =12 ---> 3x=2 ---> x=4 and 3(0)+3y = 12 ---> y=4. The points are (0,4) and (4,0)

For equation 2: 0 = -x-4 --->x=-4 and y = -(0) -4 ---> y=-4. The points are (0,-4) and (-4,0)

In each case, connect the two points. You'll see the two lines are parallel. They never intersect, so this system has no solutions.

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