You can put this solution on YOUR website! The sum of the digits of a two-digit number is 13. the value of the number is 2 more than 7 times the units digit
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let u=units digit
let t=tens digit
u+t=13
t=13-u
..
10t+u=7u+2
10(13-u)+u=7u+2
130-10u+u=7u+2
16u=128
u=8
t=5
number=58