SOLUTION: "A bank teller has 35 bills in $5, $10, and $20 denominations. The total value from these bills is $370. The total number of $10 bills and $20 bills is 7 more than the number of $5

Question 856603: "A bank teller has 35 bills in $5, $10, and $20 denominations. The total value from these bills is $370. The total number of $10 bills and $20 bills is 7 more than the number of $5. How many bills of each denomination does the teller have?"
What I have done:
x+y+z=35
5x+10y+20z=370
y+z+7=x
Then I keep getting fractions/decimals which is not correct
Found 2 solutions by Fombitz, ewatrrr:
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
Your third equation is incorrect.

"Is" is usually the tip-off word that means equals.
Try it like this and see what you get.
If you need help, please repost.
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!

Hi,
The total number of $10 bills and $20 bills is 7 more than the number of $5
y + z = x + 7
-7 + (y +z) = x
35 - (y +z) = x
28 = 2x
14 = x, number of $5 bills
(y + z) = 21 , y =
5x+10y+20z=370 |Yes! Now substitute
$90 + $10(21-z) + $20z = $370
$90 + $210 + $10z = $370
$10z = 70
z = 7, number of $20 bills. There are 14 $10 bills
CHECKING our answer***
$90 + $140 + $140 = $$370
Wish You the Best in your Studies.

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