Hi,

x+y+2z= 11 and 

x+y+3z=14 

x+y+2z= 11 and

-x-y-3z=-14   |Subtract 2nd from first to eliminate x & y

      -z = -3

     

x+y+3z=14 and 

x+2y-z=5

x+y+9=14 and    |Substitute z = 3

x+2y-3=5

x+y = 5 and 

x+2y = 8

x+y = 5 and 

-x-2y = -8    |Subtract 2nd from first to eliminate x

      -y = -3

        and x+y+2z= 11 ⇒ x + 3 + 6 = 11  

(2, 3, 3) the solution for this system 

RELATED QUESTIONS

When my professor explains this I understand.  When I get home, it is like written in... (answered by checkley75,scott8148)

I am trying to solve a linear equation with three variables and I am stuck on this... (answered by KMST)

hi I am a student in algebra 2 and we are solving linear equalities for the values of x,... (answered by josgarithmetic)

HI!

I just started Algebra 2 this year, and we are reviewing from algebra right now,... (answered by stanbon)

I am trying to solve a system of equations with three variables.
6x-y+2z=-14
x+2y-z=-2
 (answered by ewatrrr)

I am not good at these types of problems and I dont have a calculator to calculate these... (answered by amoati)

I need you to help with a graphical method.  I do not understand it or algebra to beging... (answered by mananth)

The question is to solve each system. If there is no solution or if there are infintely... (answered by ankor@dixie-net.com)

Please help!  I am so confused!

3. Solve for X, Y, and Z in the following systems of... (answered by rviksub)