SOLUTION: a 60% sulphuric acid solution will be mixed with a 90% sulphuric acid solution to produce 8 L of a 75% solution. how much of each is required

Question 841871: a 60% sulphuric acid solution will be mixed with a 90% sulphuric acid solution to produce 8 L of a 75% solution. how much of each is required
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
You will need the densities of sulfuric acid solutions. Check this:
http://www.chembuddy.com/?left=CASC&right=density_tables

60%_________1.5031 g/cc
90%_________1.8197
Unless you can find another data source (like maybe a handbook), you might try estimating the 75% concentration density, g/cc, only an estimate or prediction.

You did not say if your concentrations are w/w or w/v. You probably expect to use percent w/v. But the data in the reference source is percents w/w.

Let x = volume, ml, or the 60%
Let y = volume, ml, of the 90%
And assuming volumes are simply additive:

Pure sulfuric acid: grams of sulfuric acid.
Volume of 75% solution: grams of solution.

Compose the percentage equation to be all as percent by weight.

The volume sum equation is just , using milliliters.

Those two red-highlited equations are the system to solve, for x and y.
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