SOLUTION: solve equation using substitution X = y + 8 5x + 3y =12 so I put x in 5x = 5(y+8)+3y=12 = 8y + 40 = 12 now I subtract 40 and get 8y=-28 which give me -28/8 or y= -7/2, so when I

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Question 837118: solve equation using substitution
X = y + 8
5x + 3y =12
so I put x in 5x = 5(y+8)+3y=12 = 8y + 40 = 12 now I subtract 40 and get 8y=-28 which give me -28/8 or y= -7/2, so when I plug into y what is my answer for X. the teacher said they a reasonable solution. But I am lost, my dad says no solution, I don't really know. Im in 8th grade algebra

Answer by josgarithmetic(39617)   (Show Source): You can put this solution on YOUR website!
Clarifying what you tried to do:
.
Choose which way you are using in any given problem and use the variable consistently.
and , but and .

Your given system:
and ;
Most of what you show looks good.
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You have a formula for x as one of the given equations.
Substitute...






just as you found. (You showed one arithmetic mistake, like you intended division by 4 but wrote division by 8).
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Use the value for y to find the value of x, from your original first equation:





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SUMMARY OF ANSWER RESULTS: and .

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