SOLUTION: Solve the system by substitution.
4x – 4y = –4
y = 2x + 0
Algebra.Com
Question 81733: Solve the system by substitution.
4x – 4y = –4
y = 2x + 0
Answer by rapaljer(4671) (Show Source): You can put this solution on YOUR website!
4x – 4y = –4
y = 2x + 0
Since the second equation is in the form y =___, it will be convenient to substitute this back into the first equation!
4x - 4y = -4
4x-4(2x) = -4
4x - 8x = -4
-4x = -4
x=1
Now, substitute this into either equation. The easiest was is to use the y = __ equation.
y=2x
y=2(1)
y=2
The solution is (1,2).
Check in the OTHER equation:
4x-4y =-4
4(1)-4(2)=-4
4-8=-4 It checks!!
R^2 at SCC
RELATED QUESTIONS
solve the system by substitution:
4x-4y=0... (answered by checkley71)
solve the system by substitution:
4x-4y=0... (answered by scott8148)
Solve the system by substitution.
-x-y-z=-8
-4x+4y+5z=7... (answered by ewatrrr)
Solve the system by substitution
-x-y-z=-8
-4x+4y+5z=7... (answered by Alan3354)
Solve the system by the method of substitution.
1/2x + 3/4y = 10
3/4x - y =... (answered by Alan3354)
solve system by substitution
8x-4y=16... (answered by jim_thompson5910)
Solve the system by substitution:
2x+2y=0... (answered by tutorcecilia)
Solve the system by substitution.
2x + 2y = 0
y = 4x +... (answered by checkley71)
Solve the system by substitution
2x+2y=0... (answered by jim_thompson5910)