SOLUTION: if 500 tickets were sold. some at 40 cents. the remainder at 25 cents. The amount of money received for tickets sold at 40 cents was $70 more than the tickets sold at 25 cents. f

Algebra ->  Coordinate Systems and Linear Equations -> SOLUTION: if 500 tickets were sold. some at 40 cents. the remainder at 25 cents. The amount of money received for tickets sold at 40 cents was $70 more than the tickets sold at 25 cents. f      Log On


   

Question 816577: if 500 tickets were sold.
some at 40 cents.
the remainder at 25 cents. The amount of money received for tickets sold at 40 cents was $70 more than the tickets sold at 25 cents. find the amount of tickets that were sold at 40 cents each.
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Bunch of stuff to unscramble. Start by assigning variables.
n = how many tickets at 0.40 dollars each
m = how many tickets at 0.25 dollars each.

Immediately see, m+n=500.
Amount of money for the 40 cent tickets, 0.4*n.
Amount of money for the 25 cent tickets, 0.25*m.
'
0.4n=70+0.25m.

OKay,two equations, two unknown variables; go to it!
First simplify the second, money equation:
40n=25m+70
8n=5m+14
5m-8n=14;
'
The system to solve can be shown as: highlight_green%285m-8n=14%29 and highlight_green%28m%2Bn=500%29.
NOW go to it!