3x-2 = 15x-2y = 5 Make two equations: 3x-2 = 15x-2y (1) 15x-2y = 5 Simplify the first equation: 3x-2 = 15x-2y (2) -12x+2y = 2 Put equations (1) and (2) together as a system to solve by elimination: (1) 15x-2y = 5 (2) -12x+2y = 2 Add the two equations term by term (1) 15x-2y = 5 (2) -12x+2y = 2 ----------------- 3x = 7 x = 7/3 Substitute 7/3 for x in (1) (1) 15x-2y = 5 15(7/3)-2y = 5 35-2y = 5 -2y = -30 y = 15 Solution x = 7/3, y = 15. Edwin