# SOLUTION: Solve the following system by substitution 8x-4y=16 y=2x-4

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 Question 81194: Solve the following system by substitution 8x-4y=16 y=2x-4Answer by jainenderkapoor(61)   (Show Source): You can put this solution on YOUR website!8x-4y=16 ----(1) y = 2x - 4 ----(2) From the second equation we have y =2x - 4 ----- (3) substituting this value in (1) equation, we get 8x - 3(2x - 4) = 16 8x - 6x + 12 = 16 2x + 12 = 16 2x + 12 - 12 = 16 - 12 (subtractinc 12 from both sides) 2x = 4 2x/2 = 4/2 (dividing both sides by 2) x = 2 Putting this value of x in (3) equation we get y = 2(2) - 4 y = 4 - 4 y = 0 so solution is x = 2 and y = 0 Hope the solution is clear to you. In case you have any other doubt, please contact me on jainenderkapoor@gmail.com I am available for Online Tutoring at very reasonable rates.