SOLUTION: Luis and Julia have the same number of coins. Luis has only dimes and Julia has only quarters. If Julia has $1.80 more than Luis does, how many coins does each have?
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-> SOLUTION: Luis and Julia have the same number of coins. Luis has only dimes and Julia has only quarters. If Julia has $1.80 more than Luis does, how many coins does each have?
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Question 77716This question is from textbook Algebra Structure and Method
: Luis and Julia have the same number of coins. Luis has only dimes and Julia has only quarters. If Julia has $1.80 more than Luis does, how many coins does each have? This question is from textbook Algebra Structure and Method
You can put this solution on YOUR website! Luis and Julia have the same number of coins. Luis has only dimes and Julia has only quarters. If Julia has $1.80 more than Luis does, how many coins does each have?
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Let the number of coins each has be "x".
Value of Luis's dimes = 10x cents
Value of Julia's quarters = 25x cents
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EQUATION:
Julia value - Luis value = 180 cents
25x-10x=180
15x=180
x = 12 (number of coins each has)
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Cheers,
Stan H.
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