Question 773700: Find 3 consecutive numbers whose sum is 20 more than the second number Found 2 solutions by ramkikk66, Menjax:Answer by ramkikk66(644) (Show Source):
You can put this solution on YOUR website! Let the 3 numbers be n-1,n and n+1. The middle number is n.
Their sum = n-1+n+n+1 = 3*n.
Now from the problem statement
3*n = n + 20.
2*n = 20 or n = 10.
So the 3 numbers are 9,10 and 11.
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