SOLUTION: y^2 + (x - 88)^2 = 400

Algebra.Com
Question 771614: y^2 + (x - 88)^2 = 400
Answer by MathLover1(20849)   (Show Source): You can put this solution on YOUR website!


......this is a circle
as you can see, and ; so, the center is at (,) and radius is


RELATED QUESTIONS

x^2 + y^2 = 250 x^2 - y^2 =... (answered by ewatrrr)
Can you solve x^2 + y^2 = 250 x^2 - y^2 =... (answered by ewatrrr)
x^2+3x-88=0... (answered by Edwin McCravy)
How do you put 16(x-2)^2+25(y-3)^2=400 into standard form? (answered by solver91311)
40x^2-48x-88 (answered by jim_thompson5910,josmiceli)
L + (L x 3) 2 = 88 show formula please (answered by solver91311)
Solve the equation: In(x^2+88)=2x+3... (answered by checkley79)
300=10*a*x+49*x^2 400=(10*a+98*x)*y 300=(10*a+98*x)*z+49*z^2... (answered by ikleyn)
Find the center, vertices, and foci of the ellipse with equation x^2/400 + y^2/256 = 1. (answered by ikleyn)