Question 770163: solve application problem- system of linear equations in 3 variables
x=children $3
y=students $4
z= adult $5
1,000 tickets were sold for a play, which generated $3,800 in revenue. The ticket prices were $3 for children, $4 for students, & $5 for adults. There were 100 fewer student tickets sold than adult tickets. Find the number of each type of ticket sold.
x+y+z=1,000
3x+4y+5z=3,800
y=z-100
y-z=-100
Answer by josgarithmetic(39838)   (Show Source):
| |
|
