SOLUTION: The length of a rectangle is 9 cm more than its width. The area of the rectangle is 136 cm^2. What are its dimensions?
Algebra.Com
Question 765342: The length of a rectangle is 9 cm more than its width. The area of the rectangle is 136 cm^2. What are its dimensions?
Answer by Cromlix(4381) (Show Source): You can put this solution on YOUR website!
Width = x
Length = 9 + x
x(9 + x) = 136
9x + x^2 = 136
x^2 + 9x - 136 = 0
(x + 17)(x - 8) = 0
x + 17 = 0
x = -17 (no number x <0)
x - 8 = 0
x = 8
Width = 8cm
Length = 17cm
Hope this helps.
:-)
RELATED QUESTIONS
The length of a rectangle is 9 cm more than four times the width. If the perimeter of the (answered by stanbon)
the length of a rectangle is 2 centimeters less than its width. What are the dimensions... (answered by Alan3354)
The length of a rectangle is 15 cm more than its width. A second rectangle whose... (answered by mananth)
The length of a rectangle is 2 cm more than four times the width. If the perimeter of the (answered by user_dude2008)
The length of a rectangle is 6 cm more than its width. The perimeter of the rectangle is... (answered by ewatrrr)
The length of a rectangle is 9 cm less than twice its width. If the area of the rectangle (answered by ewatrrr)
The length of a rectangle is 9 cm more than its width what is the... (answered by greenestamps)
The length of a rectangle is 2 cm longer than its width. If the diagonal of the rectangle (answered by jorel1380)
the width of a rectangle is 8 cm. less than its length and the area is 20 sq cm. what are (answered by Fombitz)