SOLUTION: How do I find the solution set from y= x^2 - 22 and y = 4x - 1?
I don't know how to factoring x^2 - 22. As for the second linear I'm pretty sure it's (-1/4, -1)
Thank you
Algebra ->
Coordinate Systems and Linear Equations
-> SOLUTION: How do I find the solution set from y= x^2 - 22 and y = 4x - 1?
I don't know how to factoring x^2 - 22. As for the second linear I'm pretty sure it's (-1/4, -1)
Thank you
Log On
Question 765313: How do I find the solution set from y= x^2 - 22 and y = 4x - 1?
I don't know how to factoring x^2 - 22. As for the second linear I'm pretty sure it's (-1/4, -1)
Thank you Answer by josgarithmetic(39617) (Show Source):
You can put this solution on YOUR website! Factoring the quadratic equation first is unnecessary. Try substitution. You have a formula for y in the form of the linear equation, so substitute this into the quadratic equation, and then solve for x that way.
_____using substitution. ___________AND THAT IS FACTORABLE.
(