SOLUTION: When will the parabola cross the x-axis with the equation y = 1/2 x-squared + 4x -2?

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Question 761720: When will the parabola cross the x-axis with the equation y = 1/2 x-squared + 4x -2?
Answer by ramkikk66(644)   (Show Source): You can put this solution on YOUR website!

The key concept to remember is that for all points on the x axis, the y-coordinate is 0. i.e. y = 0 for all x on the x-axis.
At the point(s) where the parabola crosses the x axis, y will be 0.
In other words,
Multiplying by 2 to get rid of the fraction in the left side

This is a standard quadratic equation of the for ax^2 + bx + c = 0 with a = 1, b = 8 and c = -4.
We can solve it using the quadratic solver as shown below. The graph also shows the 2 points where the parabola intersects the x axis.
The two points where it crosses the x axis are (0.4721,0) and (-8.4721,0)
:)
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=80 is greater than zero. That means that there are two solutions: .




Quadratic expression can be factored:

Again, the answer is: 0.47213595499958, -8.47213595499958. Here's your graph:
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