SOLUTION: 25+15y+2y^2=228

Question 754329: 25+15y+2y^2=228
Answer by vidya pattar(14) (Show Source): You can put this solution on YOUR website!
Solution:
Here you have :
25 + 15y + 2y^2 = 228
now try to get rid of 228 from the right side.
25 - 228 +15y + 2y^2 =0
now combine the like terms :
-223 + 15y + 2y^2 = 0
now arange them in increasing order.
2y^2 +15y - 223 = 0
now to solve for x you have use the quadratic rquation:

Solved by pluggable solver: SOLVE quadratic equation with variable

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=2009 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: 7.45546741550748, -14.9554674155075. Here's your graph:

so here you get "
x = (-15 +/- sqrt ( 15^2 - 4(2)(-223)) )/ 2(2)
x = -15 +/- sqrt ( 2009)/4
hence we get after calculation x = 7.45 and x = - 14.955
Thanks & regards
Vidya pattar
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