SOLUTION: A man is 32 years older than his son,ten years ago he was 3 times as old as his son.find the present age of each.

Question 737416: A man is 32 years older than his son,ten years ago he was 3 times as old as his son.find the present age of each.
Answer by Susan-math(40) (Show Source): You can put this solution on YOUR website!
Let m=man's age
Then s =son's age = m-32
Man's age ten years ago was m-10
Son's age ten years ago was m - 32 -10=m-42
But we also know man 10 years ago = 3* son 10 years ago
So
Distribute and simplify:
M

Subtract m from both sides

Add 126 to both sides
and divide by 2 on both sides to get m =58.
So the man is now 58 years old. Going to the top, we find his son is 32 years younger, so his son is 58-32=26.
To check, go back ten years: the man was 48 and his son was 16 and 48=3*16.

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