SOLUTION: I am a parent trying to help my student and she has to show her work. f(x)=x to the second power -8x+3 Approximate the zeros of the functi

Algebra.Com
Question 733508: I am a parent trying to help my student and she has to show her work. f(x)=x to the second power -8x+3
Approximate the zeros of the function to the nearest tenth.

Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
f(x)=x^2 - 8x + 3
------------
Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=52 is greater than zero. That means that there are two solutions: .




Quadratic expression can be factored:

Again, the answer is: 7.60555127546399, 0.394448724536011. Here's your graph:

------------------------------

RELATED QUESTIONS

I am trying to help my son with polynomials and I am very confused. Please explain to... (answered by checkley77,jim_thompson5910)
I need help i am a parent trying to help my son with his homework his teacher gave them... (answered by ankor@dixie-net.com)
Hi, I am trying to help my granddaughter with her homework. She has the following... (answered by Alan3354)
Hello. I am trying to solve f(x)=(x-2)(x-3)to the second power. I know the answer is x (answered by Fombitz)
I AM A PARENT TRYING TO HELP MY 13 YR. OLD WITH HIS ALGEBRA. I HAVE BEEN OUT OF SCHOOL... (answered by checkley71)
I am a parent who has been out of school for more than 20 years. I am trying to help my... (answered by scott8148)
I am trying to help my daughter with her homework and it has been a while since... (answered by Alwayscheerful)
14 = 2/3(9y - 15) Please show me how to solve the problem. I am a parent trying to... (answered by tvandenberg,solver91311,MathGuyJoe)
I AM A PARENT TRYING TO HELP MY DAUGHTER DO THIS PROBLEMS I NEVER HAD THIS MAYBE YOU... (answered by venugopalramana,fractalier)