SOLUTION: 3x/ (x^2+5x+6) = 5x/ (x^2+2x-3) - 2/(x^2+x-2)

Algebra.Com
Question 712482: 3x/ (x^2+5x+6) = 5x/ (x^2+2x-3) - 2/(x^2+x-2)
Answer by lynnlo(4176)   (Show Source): You can put this solution on YOUR website!
3x(x-1)=5x(x+2)-2(x+3)
3x(x-1)-5x(x+2)+2(x+3)=0
-2x^2-11x+6=0
-((x+6)(2x-1))=0
(x+6)(2x-1)=0
x+6=0 OR 2x-1=0
x=-6 OR 2x-1=0
x=-6 OR 2x=1
DIVIDE BOTH SIDES BY 2
x=-6 OR x=1/2

RELATED QUESTIONS

((x^2-3x+2)/(x+2))X((3x)/(x-2))X((2x+4)/(5x^2-5x)) (answered by mananth,MathTherapy)
Help me to divide 3x^2-5x-2/6x^2-3x by... (answered by ankor@dixie-net.com)
(2x^(2)+5x-3)/(x^(2)+x-6)÷(3x^(2)+4x+1)/(3x^(2)-5x-2)... (answered by DrBeeee)
(x^3)-(2x^2)-5x+6=0 (answered by DrBeeee)
-5x+3+6(x+1)=2x+2 (answered by tommyt3rd)
x^3+2x^2+5x (answered by jim_thompson5910)
x/2+3x/4-5x/6=2 (answered by Fombitz)
3x/x+3*... (answered by mathstutor494)
x^2+3x+2 x^2+5x+4 ________ / _________ x^2+7x+12... (answered by stanbon)