SOLUTION: write the slope intercept form for an equation of the line perpendicular to the graph of the given equation and passing through the given point? 5y=-x+1

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Question 71085This question is from textbook
: write the slope intercept form for an equation of the line perpendicular to the graph of the given equation and passing through the given point?
5y=-x+1, (2,-5)
This question is from textbook

Answer by checkley75(3666) About Me  (Show Source):
You can put this solution on YOUR website!
5y=-x+1
y=-x/5+1/5 thus a line perpendicular to this line has a slope of 5 & passes through(2,-5)
-5=5*2+b
-5=10+b
b=-5-10
b=-15
so the equation for this line is
y=5x-15
here is the graph of these two lines
+graph%28+400%2C+400%2C+-16%2C+16%2C+-16%2C+16%2Cy+=+-x%2F5+%2B1%2F5%2C+y+=+5x+-15%29+ (graph 400x400 pixels, x from -16 to 16, y from -16 to 16, of TWO functions y = -x/5 +1/5 and y = 5x -15).