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writing equation in standard form?
y+2= -3/4 (x+1)
Standard form consists of these 7 parts in this order:
1. A positive whole number (if possible)
2. The letter x multiplied by the number in 1
3. A plus or minus sign
4. A whole number (if possible)
5. The letter y multiplied by the number in 4
6. An equal sign
7. A whole number (if possible)
y + 2 = -3/4(x + 1)
Multiply both sides by 4 to clear of fractions:
4(y + 2) = 4[-3/4(x + 1]]
Distibute the 4 on the left. Cancel the 4's on the right:
1
4y + 8 = 4[-3/4(x + 1]]
1
4y + 8 = -3(x + 1)
Distribute the 3 on the right
4y + 8 = -3x - 3
Add 3x to both sides:
4y + 8 + 3x = -3x - 3 + 3x
4y + 8 + 3x = -3
Subtract 8 from both sides
4y + 8 + 3x - 8 = -3 - 8
4y + 3x = -11
Reverse the terms on the left:
3x + 4y = -11
That's it. It has all 7 parts in the
order listed above. All the numbers
are whole numbers and the first one is
positive.
Edwin