SOLUTION: I am stuck on this Linear Systems problem.
Roy and Steve have the same number of coins. Roy has only dimes and Steve has only quarters. If Steve has $1.80 more than Roy does, ho
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Roy and Steve have the same number of coins. Roy has only dimes and Steve has only quarters. If Steve has $1.80 more than Roy does, ho
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Question 695649: I am stuck on this Linear Systems problem.
Roy and Steve have the same number of coins. Roy has only dimes and Steve has only quarters. If Steve has $1.80 more than Roy does, how many coins does each have?
Thanks in advance Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Roy and Steve have the same number of coins. Roy has only dimes and Steve has only quarters. If Steve has $1.80 more than Roy does, how many coins does each have?
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Equation:
Quantity Eq:: d = q
Value Eq:: 25q = 10d +180 cents
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Substitute for "d" and solve for "q":
25d = 10d + 180
15d = 180
d = 12 (# of dimes Roy has)
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q = 12 (# of quarters Steve has)
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Cheers,
Stan H.
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