SOLUTION: It says to write an equation in standard form for each line. I'm having trouble figuring out this one problem: the line crosses the x-axis at x=-3 and the y-axis at y=6. I was ju

Question 69080This question is from textbook Algebra 1
: It says to write an equation in standard form for each line. I'm having trouble figuring out this one problem: the line crosses the x-axis at x=-3 and the y-axis at y=6. I was just wondering if anyone could tell me how to write an equation for this? This question is from textbook Algebra 1

Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
One approach is to write the equation first in the "slope-intercpt" form, then convert this to the "standard form".
First, find the slope of the line from the given information. You have two points on the: (-3, 0) and (0, 6). These are the given x- and y-intercepts, respectively.
From these two points you can find the slope using:

So now you can write:
but you have been given b, the y-intercept. It's 6.
This is the equationin the slope-intercept form. You now need to convert it to the standard form:
Subtract y from both sides.
Subtract 6 from both sides.
or
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