SOLUTION: please help to solve : x^2 + y^2 = 25 2x - y = 5

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Question 68370This question is from textbook An Incremental Development
: please help to solve :
x^2 + y^2 = 25
2x - y = 5
This question is from textbook An Incremental Development

Answer by rmromero(383) About Me  (Show Source):
You can put this solution on YOUR website!
Solution:
Here are the Steps in solving linear Equation using Substition method
1. In either equation, solve for one variable in terms of the other.
--> 2x - y = 5 is a simple equation so we are going to choose this equation to solve for y in terms of x. You can also solve for x in terms of y but it is simplier to solve y instead.
--> -y = -2x +5 Eliminating the negative sign in y, divided both sides by -1
y = 2x - 5
2. Substitute for that variable in the other equation. Solve.
--> Use the other equation x^2 + y^2 = 25. Substitute 2x - 5 to y then solve for x.
--> x%5E2+%2B+%282x-5%29%5E2+=+25
x%5E2+%2B+%284x%5E2+-20x+%2B+25%29+=+25
5x%5E2+-+20x+%2B+25+-+25+=+0
5x%5E2+-+20x+=+0
5x (x - 4) = 0 -------------->> Zero Product Property
5x = 0 | x - 4 = 0
x = 0 | x = 4
3. Substitute the result from step 2 in either equation. Solve for the other variable.
--> 2x - y = 5 , when x = 0
2(0) - y = 5
-y = 5 ----------> divide both sides by -1
y = - 5
--> 2x - y = 5, When x = 4
2(4) - y = 5
8 - y = 5
-y = -3 ----------> divide both sides by -1
y = 3

4. Check the solution in both original equations.
When x = 0 and y = -5
x%5E2+%2B+y%5E2+=+25
0%5E2+%2B+%28-5%29%5E2+=+25
25 = 25 True
When x = 4 and y = 3
x%5E2+%2B+y%5E2+=+25
4%5E2+%2B+3%5E2+=+25
16 + 9 = 25
25 =25 True
Therefore the solutions are (0, -5) and (4, 3).