SOLUTION: the perimeter of a rectangle is 48 inches.The length is 6 inches greater than the width.Define the variables,and write equaations to represent this situation.solve the system by su

Question 681983: the perimeter of a rectangle is 48 inches.The length is 6 inches greater than the width.Define the variables,and write equaations to represent this situation.solve the system by substitution
Answer by tsewaitung(11) (Show Source): You can put this solution on YOUR website!
let the length be x and the width be y.
from the question, we have
2(x+y)=48
x=y+6
by substituting the second equaation into the first equaation, we have
2[(y+6)+y)=48
2[y+6+y]=48
2[2y+6]=48
4[y+3]=48
y+3=12

by substituting y=9 into the second equaation, we have
x=9+6

the length of the rectangle is 15 inches and the width of the rectangle is 9 inches.

RELATED QUESTIONS
The length of a rectangle is 6 inches more than the width. The perimeter is 48 inches.... (answered by jorel1380)

The width of a rectangle is x inches long. The length of that rectangle is 6 inches less... (answered by solver91311)

The width of a rectangle is x inches long. The length of that rectangle is 6 inches less... (answered by rm29924)

The length of a rectangle is 7 inches greater than its width. The perimeter of the... (answered by josgarithmetic)

The length of a rectangle is 6 inches more than width. The perimeter of the rectangle can (answered by ikleyn)

The length of a rectangle is 20 inches greater than the width and the perimeter is 160... (answered by rfer)

The perimeter around a rectangle is 48 inches. The length of the rectangle is 2 inches... (answered by rfer)

The perimeter of a rectangle is 48 inches. The width of the rectangle is 2 more than half (answered by addingup)

The perimeter of a rectangle is to be no greater than 400 inches, and the length must be... (answered by checkley71)