SOLUTION: 6(5z-1)-5(z+2)=13(z+1) Can you please help me solve this in algebric form. Thank you

Algebra ->  Coordinate Systems and Linear Equations -> SOLUTION: 6(5z-1)-5(z+2)=13(z+1) Can you please help me solve this in algebric form. Thank you       Log On


   

Question 674222: 6(5z-1)-5(z+2)=13(z+1)
Can you please help me solve this in algebric form. Thank you
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
6%285z-1%29-5%28z%2B2%29=13%28z%2B1%29 Start with the given equation.


30z-6-5z-10=13z%2B13 Distribute.


-16%2B25z=13z%2B13 Combine like terms on the left side.


25z=13z%2B13%2B16 Add 16 to both sides.


25z-13z=13%2B16 Subtract 13z from both sides.


12z=13%2B16 Combine like terms on the left side.


12z=29 Combine like terms on the right side.


z=%2829%29%2F%2812%29 Divide both sides by 12 to isolate z.


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Answer:

So the solution is z=29%2F12