SOLUTION: solve({4x+2y-6z=-38,5x-4y+z=-18,x+3y+7z=38})
Algebra.Com
Question 674128: solve({4x+2y-6z=-38,5x-4y+z=-18,x+3y+7z=38})
Answer by 3raser(1) (Show Source): You can put this solution on YOUR website!
Solution: x = -3, y = 2, z = 5.
RELATED QUESTIONS
Solve the system of equations in 3 variables.
4x+2y-6z=-38
5x-4y+z=-18
x+3y+7z=38
(answered by Edwin McCravy)
How do you solve 3 variable system equations?!
Ex: 4x+2y-6y=-38, 5x-4y+z=-18,... (answered by Fombitz)
-5x-3y=-2
-2y+6z=24
4x-7z=2
what is x,y,and... (answered by josgarithmetic)
x-3y-7z+w=11
2x-4y+6z-3w=-3
3x+2y+z+2w=19... (answered by Alan3354)
Solve the system of equations?
4x-4y-z=38
x+4y-3z=6
-3x+2y-z=-14
x=?
y=?... (answered by ankor@dixie-net.com)
x-3y+7z+w=11
2x+4y+6z-3w=-3
3x+2y+z+2w=19
4x+y-3z+w=22
Systems of linear equations (answered by Alan3354)
4x-4y-z=38
What does x... (answered by checkley75)
Help please!
I tried to solve these but I'm not sure if its correct.
4x – 3y = 1
(answered by edjones)
2x + 3z = 4
3y + 2z = 5
3x + 4y = −16
(x, y, z) =
2x +... (answered by Alan3354)