SOLUTION: I try doing but I got stuck on the last part. How do you solve ((3x^2)(6x^-1)^2/(16y^3)(5y^-1)). I got 108x^0/80y^2 but you have to simplify it which is 27/20y^2 but I do not under

Question 667884: I try doing but I got stuck on the last part. How do you solve ((3x^2)(6x^-1)^2/(16y^3)(5y^-1)). I got 108x^0/80y^2 but you have to simplify it which is 27/20y^2 but I do not understand how they got the 27 from.
Answer by MathTherapy(10552) (Show Source): You can put this solution on YOUR website!
I try doing but I got stuck on the last part. How do you solve ((3x^2)(6x^-1)^2/(16y^3)(5y^-1)). I got 108x^0/80y^2 but you have to simplify it which is 27/20y^2 but I do not understand how they got the 27 from.

You're correct up to this point:

= = 108 * 1 ------ Anything to the "0" power = 1

We now have: , which when simplified results in: --- Dividing numerator and denominator by GCF, 4

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