SOLUTION: Solve the linear system of equations 9x-7y=63 45x-35y-18

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Question 656168: Solve the linear system of equations
9x-7y=63
45x-35y-18
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

9x-7y=63
45x-35y-18...I guess you have here 45x-35y=18
Solved by pluggable solver: Solve the System of Equations by Graphing



Start with the given system of equations:


9x-7y=63

45x-35y=18





In order to graph these equations, we need to solve for y for each equation.




So let's solve for y on the first equation


9x-7y=63 Start with the given equation



-7y=63-9x Subtract 9+x from both sides



-7y=-9x%2B63 Rearrange the equation



y=%28-9x%2B63%29%2F%28-7%29 Divide both sides by -7



y=%28-9%2F-7%29x%2B%2863%29%2F%28-7%29 Break up the fraction



y=%289%2F7%29x-9 Reduce



Now lets graph y=%289%2F7%29x-9 (note: if you need help with graphing, check out this solver)



+graph%28+600%2C+600%2C+-10%2C+10%2C+-10%2C+10%2C+%289%2F7%29x-9%29+ Graph of y=%289%2F7%29x-9




So let's solve for y on the second equation


45x-35y=18 Start with the given equation



-35y=18-45x Subtract 45+x from both sides



-35y=-45x%2B18 Rearrange the equation



y=%28-45x%2B18%29%2F%28-35%29 Divide both sides by -35



y=%28-45%2F-35%29x%2B%2818%29%2F%28-35%29 Break up the fraction



y=%289%2F7%29x-18%2F35 Reduce





Now lets add the graph of y=%289%2F7%29x-18%2F35 to our first plot to get:


+graph%28+600%2C+600%2C+-10%2C+10%2C+-10%2C+10%2C+%289%2F7%29x-9%2C%289%2F7%29x-18%2F35%29+ Graph of y=%289%2F7%29x-9(red) and y=%289%2F7%29x-18%2F35(green)


From the graph, we can see that the two lines are parallel and will never intersect. So there are no solutions and the system is inconsistent.



in case you have this:45x-35y-18=0, your solution will be same as above