SOLUTION: x+y-4=0 and 2x-y-2=0 awaiting the point (0,0) find the equation of a straight line

Algebra.Com
Question 651727: x+y-4=0 and 2x-y-2=0 awaiting the point (0,0) find the equation of a straight line
Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
x+y-4=0
2x-y-2=0
------
Add and solve for "x":
3x - 6 = 0
3x = 6
x = 2
------
Solve for "y":
x + y - 4 = 0
2 + y - 4 = 0
y - 2 = 0
y = 2
===========
Cheers,
Stan H.
=============

RELATED QUESTIONS

Find the equation of the straight line passing through the point (-2,1) and through the... (answered by TimothyLamb)
find the equation of the line which passes through the point ( -2, 1 ) and is parallel to (answered by Alan3354,MathLover1)
HELP! Find the equation of the straight line, trough (4,-2) and parallel with 2x+y-5 =... (answered by richard1234)
Hello! Find the equation of the straight line, trough (4,-2) and parallel with 2x+y-5 = (answered by Maths68)
The two straight lines 3y + 2x - 7 = 0 and 2 y = x - 7 intersect at the point P. Q is the (answered by mananth)
please i want you to help me find the equation of the locus of points equidistant from... (answered by Theo,ikleyn,greenestamps)
Find the equation of a straight line l1 which is perpendicular to l2:2x+3y-1=0 at the... (answered by stanbon)
find the equation of the straight line which passes through the point (-2,6) and is:-... (answered by richwmiller)
1. What is the equation of a line that passes through points (-1, 2) and (5, 2)? y - 2... (answered by ewatrrr,MathLover1)