SOLUTION: A furniture manufacturing company manufactures tables and chairs. A table
requires 8 labor-hours for assembly and 2 labor-hours for finishing. A
chair requires 2 labor-hours
Algebra.Com
Question 65072: A furniture manufacturing company manufactures tables and chairs. A table
requires 8 labor-hours for assembly and 2 labor-hours for finishing. A
chair requires 2 labor-hours for assembly and 1 labor-hour for finishing.
The maximum labor-hours available per day for assembly and finishing are
400 and 110, respectively. If x is the number of tables and y is the number
of chairs produced per day, determine how many tables and chairs can be
assembled and finished.
Answer
x = # of tables
y = # of chairs
x + 2y = 400, assembly
8x + 2y = 110, finished
HELP!!!!
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
A furniture manufacturing company manufactures tables and chairs. A table
requires 8 labor-hours for assembly and 2 labor-hours for finishing. A
chair requires 2 labor-hours for assembly and 1 labor-hour for finishing.
The maximum labor-hours available per day for assembly and finishing are
400 and 110, respectively. If x is the number of tables and y is the number
of chairs produced per day, determine how many tables and chairs can be
assembled and finished.
Answer
x = # of tables
y = # of chairs
Assembly: 8x+2y<=400
Finishing: 2x+y<=110
-----------
Rewrite each equation in slope-intercept form:
y<=-4x+200
y<=-2x+110
--------------
Find the intersection of the two lines:
-4x+200=-2x+110
2x=90
x=45
Solve for y as follows:
y=-2(45)+110
y=20
------------
Manufacture 45 tables and 20 chairs.
Cheers,
Stan H.
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