SOLUTION: how do you solve 1-5 using the substitution method. 1. 4x+3y=11 x=3y-1 2. 2x+3y=5 x=4-2y 3. 3x-2y=11 y=5-2x 4. x+y=-5 4x-2y=10 5. y=2x-1 y=2-x

Algebra ->  Algebra  -> Coordinate Systems and Linear Equations -> SOLUTION: how do you solve 1-5 using the substitution method. 1. 4x+3y=11 x=3y-1 2. 2x+3y=5 x=4-2y 3. 3x-2y=11 y=5-2x 4. x+y=-5 4x-2y=10 5. y=2x-1 y=2-x      Log On

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Question 644307: how do you solve 1-5 using the substitution method.
1. 4x+3y=11
x=3y-1
2. 2x+3y=5
x=4-2y
3. 3x-2y=11
y=5-2x
4. x+y=-5
4x-2y=10
5. y=2x-1
y=2-x
Answer by unlockmath(1602) About Me  (Show Source):
You can put this solution on YOUR website!
Hello,
I'll do the first one, let's see if you can do the rest of them.
4x+3y=11
x=3y-1
Substitute the second equation into the first like this:
4(3y-1)+3y=11
Expand:
12y-4+3y=11
Add 4 and combine:
15y=15
Divide by 15:
y=1
Plug this into either equation to find x:
x=2
Make sense?
RJ
www.math-unlock.com