# SOLUTION: how do you solve 1-5 using the substitution method. 1. 4x+3y=11 x=3y-1 2. 2x+3y=5 x=4-2y 3. 3x-2y=11 y=5-2x 4. x+y=-5 4x-2y=10 5. y=2x-1 y=2-x

Algebra ->  Algebra  -> Coordinate Systems and Linear Equations -> SOLUTION: how do you solve 1-5 using the substitution method. 1. 4x+3y=11 x=3y-1 2. 2x+3y=5 x=4-2y 3. 3x-2y=11 y=5-2x 4. x+y=-5 4x-2y=10 5. y=2x-1 y=2-x      Log On

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 Click here to see ALL problems on Linear-systems Question 644307: how do you solve 1-5 using the substitution method. 1. 4x+3y=11 x=3y-1 2. 2x+3y=5 x=4-2y 3. 3x-2y=11 y=5-2x 4. x+y=-5 4x-2y=10 5. y=2x-1 y=2-xAnswer by unlockmath(1602)   (Show Source): You can put this solution on YOUR website!Hello, I'll do the first one, let's see if you can do the rest of them. 4x+3y=11 x=3y-1 Substitute the second equation into the first like this: 4(3y-1)+3y=11 Expand: 12y-4+3y=11 Add 4 and combine: 15y=15 Divide by 15: y=1 Plug this into either equation to find x: x=2 Make sense? RJ www.math-unlock.com